Hi there, unknown determined as 2-ethyl-1-butanol
Elemental analysis:
C - 70.6%, H - 13.7%, O - 15.7% Total = 70.6 + 13.7+15.7 = 100%, hence no other element present.
Now divide these percentages with respective element atomic mass
C:H:O = 70.6/ 12.0107 : 15.7/ 1.00794 : 15.7/ 15.9994 = 6:14:1
so molecular formula is C6H14O and molar mass of this formula gives 102.1748 g/mol
Mass:
Molecular Ion (MI OR M+) is at m/z 102
m/z 84 is due to loss of water molecule (H2O) from M+ ion
m/z 56 (peak is due to loss of gamma hydrogen through McLafferty rearrangement)
IR:
3300 cm-1, strong, broad peak is due to alcohol O-H stretch
2850-3000 cm-1, strong, sharp due to sp3 C-H stretch
1380 & 1460 cm-1, medium peaks are due to sp3 C-H bending
1050 cm-1, strong due to alcohol C-O stretch
HNMR: protons are in BOLD for respective splitting
3.5 ppm, doublet, 2H due to CH-CH2-OH fragmnet
2.1 ppm, singlet, 1H due to -OH
1.2-1.5 ppm, multiplet,5H due to -CH2-CH-CH2- fragment
0.85 ppm, triplet, 6H due to -CH2-CH3 fragment twice
NMR assignments:
Hope this helped you!
Thank You So Much!
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spectral problem its all one problem 1) identify the compounds for each group of spectra (mass,...
spectral problem its all one problem
1) identify the compounds for each group of spectra (mass,
proton, carbon and IR)
2) assign the proton and carbon and IR spectra. identify at
least two possible fragmentation on the mass spectrum
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1) identify the compounds for each group of spectra (mass,
proton, carbon and IR)
2) assign the proton and carbon and IR spectra. identify at
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1) identify the compounds for each group of spectra (mass,
proton, carbon and IR)
2) assign the proton and carbon and IR spectra. identify at
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1) identify the compounds for each group of spectra (mass,
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spectral problem its all one problem
1) identify the compounds for each group of spectra (mass,
proton, carbon and IR)
2) assign the proton and carbon and IR spectra. identify at
least two possible fragmentation on the mass spectrum
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given
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