Consider a situation in which 235 g of P4 are exposed to 272 g of O2....

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Question

Consider a situation in which 235 g of P4 are exposed to 272 g of O2.

What is the percent yield if the actual yield from this reaction is 318 g ?

Answer 1

Answer #1

Here is the Solution:

* consider a situation to 272 g of O2 in which 235 g of P4 are exposed P4 + 5O2 2P205 • molar mass of Pu= 30.97 x 4 = 123.88

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Answer 2

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