Question

Functions Content Grades 1.0 L of a 14 M solution of formic acid (k-1.8x10") was prepared. What is the pH of this solution? Somit Tries 0/2 Enough potassium formate was added to achieve a final potassium formate concentration of 16 M (assume the volume does not change). What is the pH of this new solution? Submit Answer Tries 0/2 10 mL of 10 M NaOH is added to the solution. What is the new ph? Incorrect. Tries 2/2 Previous Toes This discussion is closed. Send Fee

Answer 1

Il of 1.4M solution of formic acid (Ka) = 1.8810-4 (Hс он HCOOH НcoъН С) Hст (49) + н”, , , - о 1,4 м 2 1.6х6 1. {{СОН - t = t 1-4-х е 154 гкъ°] [н Скон ј 1, 2 x 4 и 2 — 21PX 1. - 1 /ч н а 2 , 2 х 10-1 Скт) = г /2-га хос | 12 | х = n », рк - 47 Сн®) - 1.8 Dissociation * С необk) - Снет°) - ли potenciam pomiete Hс от° * * * = Но, A cinjugate room Constant of ой , како 1-61 ka tо Вам of weak Ab : audi 1-6-n 1:4ty ° ~/, 15.8x767 2 1,0 . 32 tiq this hydrolyn Water Ч • 6-%

6. - (би) амтр. 6 3 x1 - о он • - Сој, гән ) • Io» 2 ( рпг 14 - pəн 23-РІ * lome of lom Nowh ú added added to the sota [ Nawh lo lom in lome so, gull of sola, (Nash] - 10 m, 0.1m, Нcom" Pho K, K4 ). У ху 1.4-т О• 1 л 15 см 1.31 ): 1и XI. 3 І, н- 1 : - a1, 2-