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The rate constant at 701 K is measured as 2.57 M−1⋅s−1 and that at 895 K...

The rate constant at 701 K is measured as 2.57 M−1⋅s−1 and that at 895 K is measured as 567 M−1⋅s−1. Use the value of the activation energy (Ea=1.50×10^2kJ/mol) and the given rate constant of the reaction at either of the two temperatures to predict the rate constant at 476 K.

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Answer #1

k = 2.57 Mt sec Ti= Tolk Tg = 476k Ea = 1.50x10² kJ moft = 1.508105 I molt In this ( + +) en tiden ) = 1:06105 ( tor 476) ln

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