Question Completion Status: QUESTION 1 Why don't you have to accurately record the amount of Ca(OH)2...
Solubility Product Ksp for Ca(OH)2 is determined in two separate experiments, both at the same temperature. - by titration of hydroxide in a simple saturated solution of Ca(OH)2. - by titration of hydroxide in a 0.01 M CaCl2 solution saturated with Ca(OH)2. Identify which of the following statements is either completely "True" or at least partially "False" (assuming that the activity of each ion is equal to its molar concentration in each instance): a) True False You would expect the value...
Question 5 1 pts You have a saturated solution of Ca(OH), in a flask, meaning there is some solid Ca(OH), sitting at the bottom of the aqueous solution. Which of the following will increase the Ca2+ concentration in solution? Adding water to the solution. Adding HCl(aq) to the solution. Adding KOH(aq) to the solution Adding more Ca(OH)2(s) to the flask,
Question 8 2 pts 15.0 ml of a saturated Ca(OH)2 solution is titrated with 0.050 M HCl. The equivalence point is found to be when 17.1 ml of the HCl has been added. What was the initial concentration of the [OH-]? O 0.0439 M 0 0.0219 M O 0.0285 M. O 0.0570 M • Previous Next
D Question 9 2 pts 15.0 ml of a saturated Ca(OH)2 solution is titrated with 0.050 M HCl. The equivalence point is found to be when 17.1 ml of the HCl has been added. What was the initial concentration of the [Ca2+] O 0.0439 M O 0.0285 M 0 0.0219 M O 0.0570 M
03 Question (1 point) The solubility of slaked lime, Ca(OH)2, in water is 0.185 g/100.0 mL. 1st attempt Feedback IM! See What volume of 3.00x103 MHCl is needed to neutralize 13.5 mL of a saturated Ca(OH)2 solution? * 227 x 104 mL 2 OF 4 QUESTIONS COMPLETED 030 > + VIEW:
Part A and Part B. Also question #3-post lab. (its circled) A. Molar Solubility and Solubility Product of Calcium Hydroxide Trial I Trial 3 Trial 2 25.0 1. Volume of saturated Ca(OH), solution (mL) 2. Concentration of standardized HCl solution (molU/L) 3. Buret reading, initial (mL 4. Buret reading, final (mL) 5. Volume of HCI added (mL) 6. Moles of HCI added (mol) 7. Moles of OH" in saturated solution (mol) 8. (OH1, equilibrium (mol/L) 9. (Ca2 ], equilibrium (mol/L)...
Question 1 : What volume (in mL) of a solution 0.124 M in Ca(OH)2 must we use to neutralize 25.9 mL of a solution 0.359 M in H3PO4.
please help me answer question 1 to 3, thank you Chapter 9, Solutions, Review & Extra Credit. 2 Points for each XC correct answer; 6 points total, max. Partial Credit given. Suggestions...work in teams [it will improve the learning experience] 1. Solutions-A solution forms when a solute (the smaller quantity) dissolves in a solvent (the larger quantity). In a solution, the particles of solute are evenly distributed in the solvent. A solute may be a gas, liquid or solid. A...
Data Part 1 Temperature of Ca(OH)2 solution: 20C Molarity of the HCl solution used for the titration: 0.05 M HCl Titration 1 Titration 2 Titration 3 Initial buret reading 10mL | 19 mi 2 mL 11 mL 28 mL 28 mm 36.4 q mL 8.4 ml Volume HCI used avg: 8.8 mL Part II Temperature of Ca(OH)2 solution: 84°C Molarity of the HCl solution used for the titration: 0:05 Titration 1 Titration 2 M HC Titration 3 Initial buret reading...
yes, which the data for the experiment is given in the pictures Problem #1 Use this data to calculate Ksp of Ca(OH)2. The Ca(OH) used was 15.0 ml, titrated with 0.05M HCI DATA TABLE: TITRATION OF THE SUPERNATANT LIQUID Trial 1 Trial 2 Data Volume of CaOH, solution, mL (supernatant liquid) Initial buret reading, mL Final buret reading, mL Volume of HCl required for titration, mL Equivalence point (mL) Average Kop Problem #2 R PPPPPP LABORATORY REPORT YOU MUST SHOW...