1. The answer is 20 cMs or 20 map units.
In gene mapping, the percentage of recombination indiates the distance between the genes. This distance is measured in centi morghans (in the honor of Scientist Morghan), it is abbrivated as cM or in mapunits.
2. The answer is 17%, one cross over results two recombinants.
The formula for calculation of gene distance = % of
recombinants/Total number of progeny *100.
As the distance here is 34 map units, as one cross ovre results two
recombinants, the answer here is 34/2 = 17.So, 17% of meiocytes is
expected to have a chaisma involving the region of the bivalnet
between these loci.
Looking for help with Questions 1 and 2 Problem Set 5. Linkage and Mapping 1. It...
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