2. If a population of individuals where 30% of the population has the Aa genotype, 25% of the population has the genotype aa.
What is the allele frequency for each allele (a and A)
According to Hardy weinberg law
P2+2Pq+q2 = 1
q2 = 25% = 0.25
q = square root of 0.25
q = 0.5
Then P+q = 1
P = 1 - q
P = 1-0.5 = 0.5
2. If a population of individuals where 30% of the population has the Aa genotype, 25%...
13. The following genotype frequencies are observed in a population of 500 individuals. Genotype AA Number of individuals 210 180 Aa aa 110 Total = 500 Answer the following questions about this population (6 points total). a. What is the frequency of the “A” allele? Show your work. (1 point) b. What is the frequency of the “a” allele? Show your work. (1 point) c. Does this locus appear to be at Hardy-Weinberg Equilibrium in this population? Show your work....
We have a population of 250 individuals, with the following genotype frequencies: AA = 0.30; Aa = 0.60; aa = 0.10. Calculate the frequency of the A and a allele in this population. Show your work.
The table shows a population consisting of 80 individuals for which genotypes AA, Aa, and aa have been identified and counted. This organism is a diploid, and A and a are the only alleles at the locus. Using the data from this table as a starting point, categorize each statement below as true or false. Genotype Number of individuals АА 40 Aa 30 aa 10 Total 80 The a allele frequency is 1-0.6875 = 0.3125. The number of a alleles...
The table shows a population consisting of 80 individuals for which genotypes AA, Aa, and a have been identified and counted. This organism is a diploid, and A and a are the only alleles at the locus. Using the data from this table as a starting point, categorize each statement below as true or false. Aa Genotype Number of individuals АА 40 30 aa 10 Total 80 The frequency of the A allele is 0.6875 The number of a alleles...
A hypothetical population of 100,000 humans has 68,240 individuals with the blood type AA, 28,735 individuals with blood type AB and-3025 individuals with the blood type BB. a. What is the frequency of each genotype in this population? b. What is the frequency of the A allele? 8. 2p c. What is the frequency B allele? d. If the next generation contained 250,000 individuals, how many individuals would have blood type BB, assuming the population is in Hardy-Weinberg equilibrium?
In a population, you observe 300 homozygous dominant (AA) individuals, 400 heterozygous (Aa) individuals, and 300 homozygous recessive (aa) individuals. Please show all your work while answer the following questions. What are the observed allele frequencies for this population? • observed dominant allele (A) frequency: • observed recessive allele (a) frequency: What are the observed genotype frequencies for this population? • observed homozygous dominant (AA) genotype frequency: • observed heterozygous (Aa) genotype frequency: • observed homozygous recessive (aa) genotype frequency:...
A population is made up of individuals where 74 have the A1A1 genotype, 192 have the A1A2 genotype, and 145 have the A2A2 genotype. What is the allele frequency of A1? Answer to 2 decimal places.
Imagine if we tested genotype frequencies in our hypothetical population of 145 individuals where p=.59 and q=.41, and found the following to be true of the population: 35 individuals had the AA genotype, 100 had the Aa genotype, and 10 had the aa genotype. What might we infer about the adaptive value of the heterogenous genotype? A. It has no adaptive value. B. It has been adaptive and subject to selective pressures. C. It has been selected against. D. Its...
Genotype Total #of #of Individuals Genotype Allele Allele Individuals in Parent Frequency Population # of Alleles Total # of Alleles in Allele Parent Frequency Populations 90 XD Dr 48 D = dominant allele r=recessive allele Solve for X (complete the necessary calculation to fill in the spot on the table with the X). Round to 2 decimals.
1. A particular gene in a given population of individuals has two alleles, A and a. The frequency of the A allele equals the frequency of the a allele. What are the expected genotype frequencies, assuming the population is in Hardy-Weinberg equilibrium? AA = 0.5, aa = 0.5 AA = 0.25, Aa = 0.50, aa = 0.25 O A = 0.5, a = 0.5 The answer cannot be determined because the allele frequencies are not provided.