1. Option D is correct
If a DNA strand has a sequence GTA then the mRNA will b having CAU
as codon and the anti codon on t RNA will be GUA. ( complementary
base pairings)
2. Option C is correct
Protein synthesis involves formation of mRNA from DNA via transcription and formation of proteins from mRNA via translation.
3. Option A is correct
DNA must stay inside the nucleus to protect the replication process, to avoid DNA damage, and to prevent any possible anomalies.
4. Option C is correct
DNA has thymine as one of the nitrogenous base whereas RNA has uracil in place of thymine.
5. Option B is correct
Genetic codes are universal among all organisms with few exceptions.
6. Option A is correct
Experiments by Marshall Nirenberg and Heinrich Matthaei began to decipher genetic codes.
7. Option D is correct
Introns are removed during RNA processing before the process of translation.
8. Option C is correct
During cellular differentiation different genes are expressed at different times.
9. Option B is correct
DNA: TAC CGT GGA ACT
RNA: AUG GCA CCU UGA
Protein: Methionine Alanine Proline Stop
If a DNA strand has a sequence GTA, what will be the tRNA anticodon sequence? A....
What amino acid would the Manticodon code for RNA codon table 2nd position Tot position СТА Tyr Phe Phe > eu eu Oulaa Jooo 9999 stop stop eu eu eu Let 0 - puchbucobucusura BER < Val Val Asp Ala Asp Ala Glu Ala Glu Amino Acids Keu Pro Pro His Weu Leu Gin lle Pro Thr Thr Thr Thr Asn Asn lle Ser Ser Arg lle Met Lys Lys bucoucouco Arg > Asp Asp Val Val Val Val Ala...
Table 1: Partial RPE65 protein sequence (amino acids 41-60) for the 9-year-old LCA patient. Unmutated Protein Sequence Patient's Allele 1 Protein Sequence Patient's Allele 2 Protein Sequence START...Ser-Leu-Leu-Arg-Cyc-Gly-Pro-Gly-Leu-Phe-Glu-Val-Gly-Ser-Glu-Pro-Phe-Tyr- His-Gly...STOP START...Ser-Leu-Leu-Gin-Cyc-Gly-Pro-Gly-Leu-Phe-Glu-Val-Gly-Ser-Glu-Pro-Phe-Tyr- His-Gly...STOP START...Ser-Leu-Leu-Gin-Cyc-Gly-Pro-Gly-Leu-Phe-Glu-Val-Gly-Ser-Glu-Pro-Phe-Tyr- His-Gly...STOP Table 2. Partial RPE65 protein sequence (amino acids 61-70 and 291–300) for the 11-year-old LCA patient. Unmutated Protein Sequence Patient's Allele 1 Protein Sequence Patient's Allele 2 Protein Sequence START...Phe-Asp-Gly-Gln-Ala-Leu-Leu-His-Lys-Phe...lle-Ala-Asp-Lys-Lys-Arg-Lys-Lys- Tyr-Leu...STOP START...Phe-Asp-Gly-Gln-Ala-Leu-Leu-Tyr-Lys-Phe...lle-Ala-Asp-Lys-Lys-Arg-Lys-Lys- Tyr-Leu...STOP START...Phe-Asp-Gly-Gln-Ala-Leu-Leu-His-Lys-Phe...lle-Ala-Asp-Lys-STOP Source: Data from Russell et al. (2017). Use Tables 1 and 2 to...
The next DNA sequence is the MATRICE strand of a small gene. What is the complete amino acid sequence of the encoded peptide? GTCATGGCAACATAG 5'-3 Standard Genetic Code First position (5'end) U Second position UAU Tyr UAC Tyr UCA Ser UAA StopUGA Stop UAG Stop UUU Phe UUC Phe UUA Leu UUG Leu UGU Cys UGC Cys UCU Ser UCC Ser UCG Ser UGG Trp CUU Leu CUC Leu CUA Leu CUG Leu CCU Pro CCC Pro CCA Pr CCG...
What two restriction enzymes could you use if you wanted to produce a protein that was fused to a GST-tag that could be removed using thrombin? Would this experimental design place any other tags on your protein? Here is the vector: T7 promoter lac operator Xbal rbs Ndel AATTAATACGACTCACTATAGGGGAATTGTGAGCGGATAACAATTCCCCTCTAGAAATAATTTTGTTTAACTTTAAGAAGGAGATATACATATGTCCCCT Met Ser Pro GST Ta His TagSacl ATACTAGGTTAT.627bp...GACCATCCTCCAAAATCGGATGGTTCAACTAGTGGTTCTGGTCATCACCATCACCATCACTCCGCGGGTCTGGTGCCACGCGGTAGT lle Leu Gly Tyr.. .209aa. . . Asp His Pro Pro Lys Ser Asp Gly Ser Thr Ser Gly Ser Gly His His...
Table 1: Partial RPE65 protein sequence (amino acids 41-60) for the 9-year-old LCA patient. Unmutated Protein Sequence Patient's Allele 1 Protein Sequence Patient's Allele 2 Protein Sequence START...Ser-Leu-Leu-Arg-Cyc-Gly-Pro-Gly-Leu-Phe-Glu-Val-Gly-Ser-Glu-Pro-Phe-Tyr- His-Gly...STOP START...Ser-Leu-Leu-Gin-Cyc-Gly-Pro-Gly-Leu-Phe-Glu-Val-Gly-Ser-Glu-Pro-Phe-Tyr- His-Gly...STOP START...Ser-Leu-Leu-Gin-Cyc-Gly-Pro-Gly-Leu-Phe-Glu-Val-Gly-Ser-Glu-Pro-Phe-Tyr- His-Gly...STOP Table 2. Partial RPE65 protein sequence (amino acids 61-70 and 291-300) for the 11-year-old LCA patient. Unmutated Protein Sequence Patient's Allele 1 Protein Sequence Patient's Allele 2 Protein Sequence START...Phe-Asp-Gly-Gln-Ala-Leu-Leu-His-Lys-Phe...lle-Ala-Asp-Lys-Lys-Arg-Lys-Lys- Tyr-Leu...STOP START...Phe-Asp-Gly-In-Ala-Leu-Leu-Tyr-Lys-Phe...Ile-Ala-Asp-Lys-Lys-Arg-Lys-Lys- Tyr-Leu...STOP START...Phe-Asp-Gly-Gln-Ala-Leu-Leu-His-Lys-Phe...lle-Ala-Asp-Lys-STOP Source: Data from Russell et al. (2017). Use Tables 1 and 2 to...
2. On the mRNA codon table, the first nucleotide in mRNA is to the left, the second is above, and third is to the right. On the sequence, the 5'cap is indicated by (5'). The poly (A) tail is not shown. Use the codon table to translate this short mRNA. Mark the codons and write the amino acid sequence beneath them. (5') CGUUACAAUGUAUCGCGCGGUACUCGGCAAAGUGCCCUGAAUAGAGUUGGUA (3') 3. DNA polymerase made a mistake and added a C on the DNA template strand. In...
Question 10 (15 points) Given the following sequence for a template strand of DNA 3 - ATACTTTGTCGAGACCCGCTTCTTGCAGACTGGG A. Provide the mRNA sequence following transcription (include polarity) B. Provide the amino acid sequence using either the one letter or three letter abbreviations. Include polarity (N-or C-terminus) and be careful to start in the correct place: C. What if the "C" underlined above was changed to a T. What is the new codon? How does that affect the amino acid sequence? What...
2) On your first day working in my lab, you obtain the following DNA sequence: 3' AATTATACACGATGAAGCTTGTGACAGGTTTCCAATCATTAA 5 5' TTAATATGTGCTACTTCGAACACTGTECCAAAGGTTAGTAATT 3' a) What are the two possible RNA molecules that could be transcribed from this DNA? Indicate the 5' and 3' ends of the RNA. b) Only one of these two RNA molecules can actually be translated. Explain why. c) It turns out that the RNA molecule that can be translated is the mRNA for p53. What is the amino...
Based on the chemical properties of the residues, which of the following sequences could form the following? At least one should be placed in each category. Based on the chemical properties of the residues, which of the following sequences could form the following? At least one should be placed in each category Most likely an amphipathic Most likely an amphipathic B sheet a helix Most likely a turn/ loop Not amphipathic Asn-Leu-Ala-Asp-Ser-Phe-Arg-Gin-lle Lys-Ser-Thr-Asn-Glu-Gin-Asn-Ser-Arg Gin-lle-Thr-Phe-Thr-Leu-GIn-Val-Ser Lys-GIn-Asn-Glu-Pro-Arg-Ala-Asn-Glu Arg-Phe-GIn-lle-His-Val-Gin-Phe-Glu Ala-Phe-Leu-Val-lle-Trp-Phe-Val-Ala
If mutations occur at random, and changes to 1st or 2nd "letter" of a codon usually changes the amino acid coded for, but changes to the 3rd "letter" rarely do, roughly what % of mutations should be synonymous? Second АТ G UUU Phe UCU Ser UAU Tyr UGU Cys U 0 C | Phe UCC Ser UAC Tyr UGC Cys C Leu UCA Ser UAA Stop UGA Stop UUG Leu UCG Ser UAG Stop UGG Trp G CUU Leu CCU...