Homework Answers
The given protein contains two
polypeptide chains linked together by disulfide bonds.
Trypsin is a protease that cleaves at the C-terminal end of
positively charged amino acids such as Lysine and Arginine.
Lysine = K
Arginine = R
In the given peptide, there are two
arginines and two lysines. However, one lysine residue is followed
by Proline. So, it cannot be cleaved by trypsin.
Even after the proteolytic cleavage, the disulfide bond remains
intact (Under nonreducing conditions).
So, the number of fragments produced = 3
If disulfide bonds are reduced by
treatment with beta-mercaptoethanol,
The number of fragments produced = 5
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Please help me solve this genetics problem, my professor wasn't
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Please explain, Thanks!
The following image shows the 20 amino acids found in proteins. OH CH H HNCOOH Glycine HN HẠN CHO Alanine HẠN COOH Serine н соон Threonine Cysteine HAN COOHHN COOH Nлсоон н соон Methionine Valine Leucine Isoleucine Proline OOH MNCOOHHN COOH HN COOH H COOH HẠNỐIOOH Apartic Acid Phenylalanine Tyrosine Tryptophan Glutamic Acid HNCOOHH COOH Asparagine Glutamine HNCOOHNCOOH Histidine Lysine н соон Arginine Imagine that in a protein, a lysine amino acid is replaced with an isoleucine....
anyone can help me with it?
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Please explain
Exercise 4-determine the position of the disulfide bonds in the intact protein . Treatment of a small protein with 2-mercaptoethanol yields 2 polypeptides with the following sequences: o Y-K-C-F-R-H-T-K-C-S o A-V-C-R-T-G-C-K-N-F-L Treatment of the intact protein with trypsin yields fragments with the following amino acid compositions (note, these are no the sequences!) o (A,R,C,c.s,v) o (R,C,C,G,K.T.F o (N,L,F o (H,K,T) o (K,Y)
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