Question

Question 2 (1 point) 5'-TTAGGG-3' 3'-AATCCC-5' In this sequence, how many hydrogen bonds and phosphodiester bonds are present? O 15,10 O 12,5 O 15.5 O 12,10

Answer 1

5'- TH THALG G G7 - 31 T T T M H TT 3'-TA TAI CICHC - 5' 10 = 15 = + Phosphodiester bondes present between two adjacent bases.' Hydrogen bonds between two bases. 1

9. 2] Answer:- Option number 1 is correct. Jn given sequence, 15 Hydrogen bonds & 10 phosphodiester bonds are present. Accorcling to base pairing rule, Adenine. CA) pair with thymine (T) using two bydrogen bonds cohile Gaunine Cari pair with cytosine cc) coith three hydrogen bonds. o :. In our sequence, A-T bonds x 2 = 3x2 = 6 G-C bonds x3 = 3 X3 = 9 :: 6+9 = 15 Hydrogen bonds are present. i Phosphodiester bonds are found in same Strond & is a formed between two ribose & phosphate group. Each sugar is bonded to other by phosphodiester bond. Hence we can easily count: phosphodiestes bonds by counting the nucleotide bases. Our Sequence contain 10 phosphodiester bonds, as double Strand is present.. Each strand has 5 phosphodiester bond. or simply by using formula a(0-1) for double Strand sequence, we can count phospho- -dliester bonds present in Sequence.