I believe the correct answer to be:
Option E) 64.
As possible combinations are number of possible nucleotide to the power number of available locations:
43 = 64.
But in reality there are only 61 that code for amino acids and 3 are stop codons that do not code for anything.
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help! Question 9 1.3 pts of codons that code for 20 amino acids? 16 600 60
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