Question

PPPPPP Step 5: Determine the phenotype of cach possible allele combination shown in the offspring. In this instance, three of the offspring Chose with the genotypes EE, Ee, and Be) have free earlobes, because the free earlobe allele is dominant to the attached-carlobe allele. One offspring, ec, has attached earlobes. Therefore, the proba- bility of having offspring with free earlobes is 3/4 and with attached earlobes is 1/4. Additional Single-Factor Inheritance Problems (One Trait Followed from One Generation to the Next) 1. In humans, six fingers (F) is the dominant trait: five fingers (f) is the recessive trait. Assume both parents are heterozygous for six fingers. What are the phenotypes of the father and the mother? What is the genotype of each parent? What are the different gametes cach parent can producc? What is the probability of having six-fingered children? Five-fingered children? a. Father's phenotype mother's phenotype b. Father's genotype mother's genotype c. Father's gametes – oor mother's gametes_ d. Probability of a six-fingered child - e. Probability of a five-fingered child (2) If the father is heterozygous for six fingers and the mother has five fingers, what is the probability of their offspring having each of the following phenotypes? Six fingers L; five fingers 3. In certain flowers, color is inherited by alleles that show lack of dominance (incomplete dominance). In such flowers, a cross between a homozygous red flower and a homozygous white flower always results in a pink flower. A cross is made between two pink flowers. Use F to represent the white allele and FR to represent the red allele. What is the probability of each of the colors (red, pink, and white) appearing in the offspring? t's white Flered EF 114 - FFR = 2510 214=FFR-500 152 FRF" - Pink IN FFFN TENEW 114 - FFW - 250

Answer 1

1) both parents are heterozygous means both parents have the dominant allele and the recessive allele. since the six fingers is the dominant trait phenotype of both parents is six fingers and their genotype is Ff.

Fathers phenotype: six fingers, Mothers phenotype: six fingers

Father`s genotype: Ff, mothers genotype: Ff

both father and mother can produce 2 types of gametes F and f.

gametes produced y father F and f.

gametes produced by mother are F and f.

Ff * Ff

	F	f
F	FF ( six fingers)	Ff( six fingers)
f	Ff( six fingers)	ff ( five fingers)

Probability of getting progeny with six fingers= number of progeny with six fingers/total number of progeny=3/4

probability of getting progeny with five fingers= number of progeny with five fingers/total number of progeny=1/4

2) genotype of the father heterozygous for six fingers is Ff and genotype of the mother with five fingers is ff

Ff * ff

	F	f
f	Ff( six fingers)	ff ( five fingers)

probability of getting progeny with six fingers= number of progeny with six fingers/total number=1/2

probability of getting progeny with five fingers= number of progeny with five fingers/total number of progeny=1/2