Homework Answers
3.
(a) RRTT X rrtt
Rough coat and calm temperament Smooth coat and stubborn
temperament
Gametes RT rt
F1 RrTt (Heterozygous rough coat and calm temperament)
(i) RRTT (Rough coat and calm temperament )
(ii) rrtt (Smooth coat and stubborn temperament )
(iii) RrTt (F1 Progeny)
(b) TEST CROSS
Since recombinant frequency is 16% so the parental types will be 84%.
F1
|
Gametes |
rt |
|
RT |
RrTt (Rough coat and calm temperament) Parental Typ (42%) |
|
Rt |
Rrtt (Rough coat and stubborn temperament) (8%) |
|
rT |
rrTt (Smooth coat and calm temperament) Recombinant (8%) |
|
rt |
rrtt (Smooth coat and stubborn temperament). Parental type (42%) |
8% progeny will be rough fur and stubborn. This progeny is recombinant.
(c) (i) True breeding, Smooth fur and calm temperament (rrTT)
(ii)True breeding, Rough far and stubborn temperament (RRtt)
rrTT X RRtt
Gametes rT Rt
(iii) F1 RrTt ( Rough coat and Calm temperament)
(d) TEST cross with progeny of cross C
RrTt (F1 heterozygote) x rrtt (Smooth coat and stubborn temperament )
8% progeny will be rough fur and stubborn. This progeny is recombinant.
Answer will remain the same since the F1 progeny in cross A and cross C have the same genotype.
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