Question

I included everything here , but i only need help with parts C-F

You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body phenotype and smooth wings are dominant to crinkled wings. .) You cross a true-breeding yellow-bodied, smooth-winged female with a true-breeding red-bodied, crinkle-winged male. What will be the phenotype(s) of the F1 progeny? b) To determine the recombination frequency between these two genes, you perform several crosses where you cross an F1 from part (a) with a yellow-bodied, crinkle-winged fly. You get the following results. What is the distance between the genes for body color and wing surface in map units? body Numbe red red wing surface crinkled smooth crinkled smooth 396 102 98 404 yellow yellow You decide to turn your attention to a different gene, one that controls wing length. This gene has two alleles, "L or l" where long wings are dominant to short wings. Remember that the red body phenotype is dominant to the yellow body phenotype. You again mate two true-breeding lines: red-bodied, short wing male X yellow-bodied, long wing female F1: All red-bodied, long wing

Answer 1

Let BBll represent red bodied short wing male and bbLL represnt yellow bodied long wing female. The cross between these two parents is as follows

Parental generation: BBll $\times$ bbLL

F1 generation: BbLl (red bodied long wing)

now the F1 is crossed with a yellow bodied short winged fly, the cross is follows

BbLl  $\times$ bbll

1 red bodied long winged (BbLl) Recombination frequency=%, distance between two genes is 4.5 map unit

45 x 100 = 4.5

1 red bodied short winged (Bbll) ; Recombination frequency=% distance between two genes is 46 map units

460 1000 X 100 = 46

1 yellow bodied long winged (bbLl);  Recombination frequency=% distance betweeen two genes is 44 map units

440 1000 70 x 100 = 44

1 yellow bodied short winged (bbll); Recombination frequency=%   distance betweeen two genes is 5.5 map units

55 1000 X 100 = 5.5

d. The F1 generation (BbWw) is crossed with yellow bodied crinkled wings (bbww) gives the following genotypes

red crinkled (Bbww); distance=39.6 map units

red smooth (BbWw); distance=10.2 map units

yellow crinkled (bbww); distance=9.8 map units

yellow smooth (bbWw); distance=40.4 map units

The genes for wing length are more crossed over than the genes for wings surface, ie the latter is more tightly linked than the former.

e. has been discussed earlier

f. The cross between true breeding red bodied short and crinkle winged male (BBllww) with a true breeding yellow bodied long and smooth winged female (bbLLWW)

parental generation: BBllww  $\times$ bbLLWW

F generation: BbLlWw (red bodied long and smooth winged)