If Angiotensin-converting enzyme 2 is present in lung cells at 1000 copies/cell, how many cells do you need to grow in order to provide 100 fmol for the identification of novel phosphorylation sites in Angiotensin-converting enzyme 2?
One mole of any substance contains 6.023 X 1023 copies of it. So, 1 M of Angiotensin-converting enzyme 2 has 6.023 X 1023 copies of it. 100 fmol = 10-13M, which has 6.023 X 1010 copies of it. It was given that,the lung cells have 1000 copies of this enzyme per cell. So, to get 6.023 X 1010 copies of enzyme, the number of cells required is 6.023 X 1010 / 1000 = 6.023 X 107 cells.
If Angiotensin-converting enzyme 2 is present in lung cells at 1000 copies/cell, how many cells do...
5.To gain entry, spikes of the SARS-CoV-2 bind to
angiotensin-converting enzyme 2 (ACE2) found in epithelial cells
especially of the respiratory and oral passageways. As such, these
cells are susceptible to infection by SARS-CoV-2. ACE2 is a protein
consisting of multiple alpha-helices that is embedded in, and
spans, the membrane. What is this type of protein called, and what
structure do the alpha helices represent?
6.Following binding of spike proteins to ACE2, SARS-CoV-2 likely
gains entry into the cell either...
1) If a restriction enzyme cuts a circular DNA into five fragments, how many restriction sites are there in the DNA? 2) How many molecules of DNA will be present after 6 cycles of PCR, if you started with one double-stranded DNA molecule? CELL BIOLOGY QUESTIONS!! SHOW WORK PLEASE
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