Question

01. If a woman starts ovulating at 13 and stops at 50. a) how many ova are likely to be released from her ova b) about how many of these ova are likely to be fertilizer Q2. If mating takes place a) two days before ovulation, is fertilisation likely to occur? Explain your a y to occur? Explain your answer. b) two days after ovulation, is fertilisation likely to occur? Explain your answer. Q3. Identify the types of twins and explain how it occurs.

Answer 1

Answer =

1.If a woman starts ovulating at 13 and stops at 50

a) The number of ova likely to be released from her ovaries are 456  ova.

Explanation =

The ovaries releases ova during the time of ovulation.Usually a single ova from from one ovary is released during each menstrual cycle,with each ovary taking an alternate turn in releasing an ova.

it means that for each menstrual cycle = 1 ova.

menstrual cycle occure after 28 days

a woman starts ovulating at 13 and stops at 50

Total ovulation period = 37 years = 37 X 365   = 12775 days.

Total number of menstrual cycle = 12775 / 28 = 456

The number of ova likely to be released = 456 ova

therefore, The number of ova likely to be released from her ovaries are 456  ova

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b) The ova are likely to be fertilised are 456

because each and every ova has ability to be fertilized by sperm.

there is chances for fertilization of 456 ova by sperms.

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2.If mating takes place

a) Two days before ovulation, fertilization likely to occur because:

ovulation is the period of release of ova from ovary.if fertilization takes place before two days it means that sperms are enter into the female reproductive system.

sperm can live in fertile cervical mucus for upto 5 days.ova can live upto 24 hours after ovulation.

it means that if intercourse happens two days before ovulation, fertilization takes place.

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b)Two days after ovulation, fertilization likely to occur because:

but the chances are decreased.because ova can live upto 24 hours after ovulation.

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