Question

Merfolk have three pairs of autosomes and one sex chromosome; males are X0 and females are XX.

In merfolk the genes controlling tail fin shape and scale colour are on different autosomes. Solid tail fin (Ff) is dominant to forked tail fin (ff), and the F allele is recessive lethal. There are two alleles of the scale colour gene – C^B(blue) and C^R (red)– C^B and C^R show incomplete dominance with heterozygotes being purple.

The silent trait is X-linked and dominant (X^S) to normal voice (X⁺).

Atolla is a male merfolk, he has a forked tail fin, blue scales, and is voiceless (silent). Brachy is a female merfolk with a solid tail fin, purple scales and a normal voice.

Question -

You mate a female merfolk with blue scales who is heterozygote for silent and a carrier of forked tail, to a silent male with blue scales who is also a carrier of forked tail. Which of the following are TRUE statements (you can choose more than one)

For this question ignore the phenotypes that are unmentioned. For example "a blue female" is a blue female who can be any colour, and either be silent or normal.

Select one or more:

a. This mating can produce silent or normal voiced female offspring

b. This mating can produce silent or normal voiced offspring

c. The probability of a female offspring having a forked tail and blue scales is 1/3

d. The probability of an offspring from this mating having a forked tail and normal voice is 1/6

Answer 1

Answer : "a"

Explaination: Silent trait is X- linked and domintant to other traits mentioned leads to that - the mating can produce silent or normal voiced female offspring