Question

1a. A batch of cells are found to contain 300 mM gluco cell. The cell membrane has pores which are permeable to glucose Cound to contain 300 mM alucose and 150 mM Cach inside the ions. These cells are then placed in a NaCl solution which has an osmolarity of milliosmoles. What happens to the cells after the solution comes to equilibrium? (2 Points) a. The cells remain the same size as they were originally b. The cells swell C. The cells shrink d. There is not enough information given in the problem to determine what happens 1b. You now find new cells which contains 200 mm CaCl and 15 mM glucose. The cell membrane is permeable to Ca++ ions, impermeable to Cl-ions, impermeable to Na ions and impermeable to glucose. You transfer these cells into a solution which has 140 mM (NaCl) and 150 mM glucose. What happens to the cells after the solution and cell have come to equilibrium? (2 Points) a. They cells are the same size as they were originally b. The cells have swelled c. The cells shrank d. There is not enough information given to determine what happens 1c. An new group of cells is found to contains 300 mM glucose and 150 mm CaCl2 inside the cell. The cell membrane of the cells is not permeable to glucose or to ions. These cells are then placed in a CaCl2 solution which has an osmolarity of 450 milliosmoles. What happens to the cells after the solution and cells have come to equilibrium? (2 Points) The cells remain the same size as they were originally b. The cells swell c. The cells shrink d. There is not enough information given to determine what happens 1d. You now find a new group of cells where the interior contains 150 mM CaCl. The cell membrane of the cells is not permeable to ions but is now permeable to alucose. You place these cells into a solution which has 200 MM (NaCl) solution with 100 mM glucose. What happens to the cells? (2 Points) a. They remain the same size as they were originally b. The cells swell c. The cells shrink d. There is not enough information given to determine what happens

Answer 1

1a ) answer will be C option cell shrink as NaCl is 450millimol as compared to 150millimol inside of cells so ions cannot moe outside but water can move from inside to outside and hence size of cell shrink.

1b) Na+ ions move inside as well as water move outside and hene cell again shrink option C is correct.

1c) again cell shrink as 450mOsmol is equal to 450mM of CaCl2 which is present outside as compared to 15mM of CaCl2 present inside and hence water move out and cell again shrink so option correct.

1d) here information about glucose conc. Pesent insidse is misssing than we cannot conclude anything so option will be d there is no enough information given to determine what happen

But if we assume that there is no glucose present inside (as information about glucose conc inside the cell is missing), then water will move outside as more conc. Of glucose is present outside. And hence cell size wil shrink.

Hope ts clear.. thanks