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2. You have a fly strain heterozygous for a reciprocal translocation between an acrocentric chromosome (solid) and a metacent

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A) Note that if recombination is not an option then the gametes will be each chromosome per se. These are the resulting gametes:

ABFG/KNQR

abfqr/KNQR

ABFG/kng

abfqr/kng

B) We have to make a punnet square for this, then eliminate any individual without the two G/g copies and calculate frequencies for such resulting individuals.

ABFG/KNQR abfqr/KNQR ABFG/kng abfqr/kng
abfg/knqr AaBbFfGg/KkNnQqRr aabbffgqr/KkNnQqRr AaBbFfGg/kknngqr aabbffgqr/kknngqr

Note that the highlighted offspring lacks the two copies for gene G, that means such individual will never develop. So the observed frequencies will be:

1/3 = AaBbFfGg/KkNnQqRr

1/3 = AaBbFfGg/kknngqr

1/3 = aabbffgqr/kknngqr

We can state this because we know that alleles segregate in reproductive events, just like the second law of Mendel states (Law of segregation). We can actually get to this conclusions because we know that some of these genes are linked because they are in the same chromosome. That actually goes against the third law that states all alleles segregate independently (Law of independent assortment), but science actually refused such law around a century ago

C) We can see there is a trisomy for the first pair in question. Trisomies occur when there are problems during segregation in either Anaphase I or Anaphase II. If the issue in question is about segregating the homologous chromosomes (which actually is the case in this exercise) then it occured during Anaphase I, if the issue is about segregating sister chromatides then it occured during Anaphase II.

In this case a spermatocyte had a problem segregating homologous chromosomes during Anaphase I, leading to a final sperm cell with both homologous chromosomes for that pair. Such sperms managed to fecundate an egg and produced this individual with such trisomy.

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