Recombination is a process of genetic exchange that is mostly guided by a region of homology between the recombining DNA sequences. In the given question, one needs to analyze the pattern of appearance or lack of recombinants when deletion mutants (Benzer’s A cistron) are recombined with rII mutations of bacteriophage T4.
Therefore, a (+) would indicate presence of homology in the region, whereas a(-) indicates lack of homology and hence no recombination.
For finding out the exact regions, we should look for deletion mutants that do not show recombination with the bacteriophage T4 rII mutants and mark the regions that is deleted in the deletion mutants.
For example, consider mutant r1, it shows recombination with all deletion mutants except 1695 (this has a deletion in region 7 onwards). This indicates that r1 region of homology is present in region 7 onwards. However, r1 recombines with deletion mutants PT153 (deletion region 8 to 10), H88 (deletion region 9 onwards), 184 (deletion region 11 onwards). All these observations indicate that r1 has a mutation in the region 7 to 8. This is deduced by removing the overlap regions between the (+) recombinants and (-) recombinants.
Using this logic we can complete the table
Mutant # |
Region |
Explanation |
r1 |
7 to 8 |
(-) for 1695 (region 7 onwards) but positive for PT153 (8 to 10), H88 (9 onwards), 184 (11 onwards) |
r2 |
1 to 2 |
(-) for 1364 (1 to 6) but (+) for 386 (2 to 4), 168 (3 to 5) |
r3 |
8 to 9 |
(-) for 1695 (7 onwards), (-) for PT153 (8 to 10) but (+) for H88 (9 onwards) and 184 (11 onwards) |
r4 |
3 to 4 |
(-) for 1364 (1 to6), (-) for 168 (3 to 5) but (+) for 386 (2 to 4) |
4. (2 pts) The following illustrates a set of Benzer's "A" cistron in the rll region)...
During the course of his experiments. Seymour Benzer discovered over 20.000 mutations in the rit region of T4 bacteriophage. He classified the mutations into two categories: 1) revertible mutants (which result from point mutations), and 2) nonrevertible mutants which result from deletion mutations Fourni partial deletion mutations were tested for their ability to complement five point mutants Use the data in this table to place the point mutants in order on the ill deletion gte map below. Note: A plus...
Required information Shown below are the maps of a series of rll-deletion strains (1–5). The deleted region is indicated as (.....) and the intact region as 1 N (............. 3 ....................... 4 ........) 5. rll-phage strains A-E have point mutations in the rllregion. E.coli K(A) cells are coinfected with one phage that has a deletion and one phage that has a point mutation. The presence of wild-type progeny phage is assessed by the presence (+) or absence (0) of plaques....
Required information Shown below are the maps of a series of rll-deletion strains (1-5). The deleted region is indicated as (...) and the intact region as 1 2 ...........) 3................. 4 5 rll-phage strains A-E have point mutations in the ill region. E.coli (A) cells are coinfected with one phage that has a deletion and one phage that has a point mutation. The presence of wild-type progeny phage is assessed by the presence (+) or absence (o) of plaques. 12345...
Bi2030 (12) Defining the gene 36 1210 A set of 10 deletion mutants of some unspecified organism (#1-10) are tested for the production of 1 x2 4 x 10 ambiscity 2 x 7 5 x 8 wild-type recombinants when crossed pairwise to .2 x 10 5x9 12 7.1 O S one another. All tests are positive except those 3x6 5 x 10 shown on the night: 3x9 7 x 10 3 x 10 8x9 (a) Construct a map of these...
B12030 (12) Defining the gene E cow mutants are isolated that cannot utilize tetrahydro-cannabinol (THC) as a source of carton. energy or anything else. The map positions in minutes of the the mutations are 18 minutes #2.4 5.0.7. 10, 11, 12, 13]. [42 minutes. M 1: 151 minutes: 391: 166 minutes: #8: (85 minutes: #141 fa) What is the minimum number of genes involved in THC utilization? OVA. AM 2 5 6 7 10 11 12 13 4 0 0...