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1. You cross true breeding yellow crossveinless forked (y, cv, and fare autosomal genes) female flies...
We crossed pure-bred female flies with yellow body and forked-shaped bristles with male flies extra bristles....
We crossed pure-bred female flies with yellow body and
forked-shaped bristles with male flies extra bristles. The
subsequent F1 flies showed all normal phenotypes except that all of
the F1 males are yellow-body. We crossed again the normal F1
females with males homozygous for yellow body, extra bristles, and
forked bristles as a testcross. The number of each category of F2
progeny is shown below. The mutant allele for yellow body is y; the
mutant allele for extra bristles is...
In the Australian sheep blowfly an autosomal gene yellow (alleles y, y + ) determines the...
In the Australian sheep blowfly an autosomal gene yellow (alleles y, y + ) determines the recessive phenotype yellow eyes. A pure breeding strain with yellow eyes is crossed to a pure breeding wild-type strain. The F1 flies from this cross are allowed to interbreed to produce the F2 generation. 41 The phenotype of the F1 flies will be A. wild type B. yellow eyes C. recessive D. y + y 42 The F1 flies are testcrossed, the phenotypic ratio...
A cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ch....
A cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ch. A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut . The F, females were wild type for all three traits. • The F, males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data...
Colorium is an autosomal dominant trait in Nutonian flies (identical to earth fruit flies in every...
Colorium is an autosomal dominant trait in Nutonian flies (identical to earth fruit flies in every way). There are two alleles at this locus: F = Dominant allele; flies with this allele cannot observe the color Fuschia; these flies have the Colorium phenotype. + = Wild type allele; flies who are homozygous for this allele can observe the color Fuschia; these flies do not have the Colorium phenotype. A cross of a true breeding male with Colorium and a true...
6. In Cross 1, a yellow eyed, long wing fruit fly from a pure breeding strain...
6. In Cross 1, a yellow eyed, long wing fruit fly from a pure breeding strain is mated to a red eye, short wing fruit fly from a pure breeding strain. All of their offspring (F1) had red eyes and long wings. In Cross 2, one of the F1 offspring is mated to a fly with yellow eyes and short wings, and this cross gave the following F2 population: 194 flies with long wings and red eyes, 796 flies with...
please answer the question and explain the concept If you scored 28 females and 22 males...
please answer the question and explain the concept
If you scored 28 females and 22 males Drosophila flys, populate the table below in the appropriate phenotype area. Phenotype of No. of Males No. of Total F1 Progeny Females light brown, unforked, crossveins yellow, forked crossveinless other (if any) Total If the genetic cross was set up correctly, show the phenotype and genotype of the flies that you would expect to see. Students sometimes see F1 Offspring with unexpected phenotypes. What...
(1) A Drosophila male from a true-breeding stock with scabrous eyes and normal bristles was mated...
(1) A Drosophila male from a true-breeding stock with scabrous eyes and normal bristles was mated with a female from a true-breeding stock with normal eyes and javelin bristles. Both scabrous eyes and javelin bristles are autosomal recessive mutant traits. The F1 progeny all had normal eyes and normal bristles. F1 females from this cross were mated with males with both scabrous eyes and javelin bristles. a. Write all the possible phenotypic classes of the progeny that could be produced...
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We...
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: 3 Female: 9 Dark body color (ebony) = e Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if...
A mutation in the Drosophila bristle gene (fb) (which is X-chromosome linked) causes a recessive forked...
A mutation in the Drosophila bristle gene (fb) (which is X-chromosome linked) causes a recessive forked bristle phenotype (rather than the normal type of bristle). Another mutation in Drosophila autosomal body color gene (BR) causes a recessive brown color body (rather than the normal black body). A geneticist carried out the following cross: X+ / Y ; BR/br x X+/ Xfb ; BR/br If total of 240 F1 progeny were obtained, the “expected” numbers are: normal bristle male progeny -...
I included everything here , but i only need help with parts C-F You are working...
I included everything here , but i only need help with parts
C-F
You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body...
We crossed pure-bred female flies with yellow body and
forked-shaped bristles with male flies extra bristles. The
subsequent F1 flies showed all normal phenotypes except that all of
the F1 males are yellow-body. We crossed again the normal F1
females with males homozygous for yellow body, extra bristles, and
forked bristles as a testcross. The number of each category of F2
progeny is shown below. The mutant allele for yellow body is y; the
mutant allele for extra bristles is...
A cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ch. A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut . The F, females were wild type for all three traits. • The F, males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data...
6. In Cross 1, a yellow eyed, long wing fruit fly from a pure breeding strain is mated to a red eye, short wing fruit fly from a pure breeding strain. All of their offspring (F1) had red eyes and long wings. In Cross 2, one of the F1 offspring is mated to a fly with yellow eyes and short wings, and this cross gave the following F2 population: 194 flies with long wings and red eyes, 796 flies with...
please answer the question and explain the concept
If you scored 28 females and 22 males Drosophila flys, populate the table below in the appropriate phenotype area. Phenotype of No. of Males No. of Total F1 Progeny Females light brown, unforked, crossveins yellow, forked crossveinless other (if any) Total If the genetic cross was set up correctly, show the phenotype and genotype of the flies that you would expect to see. Students sometimes see F1 Offspring with unexpected phenotypes. What...
(1) A Drosophila male from a true-breeding stock with scabrous eyes and normal bristles was mated with a female from a true-breeding stock with normal eyes and javelin bristles. Both scabrous eyes and javelin bristles are autosomal recessive mutant traits. The F1 progeny all had normal eyes and normal bristles. F1 females from this cross were mated with males with both scabrous eyes and javelin bristles. a. Write all the possible phenotypic classes of the progeny that could be produced...
3) Dihybrid cross: The dark-bodied and rudimentary winged genes are on two different autosomal chromosomes. We will use this cross to determine the ratios of phenotypes in the F2 generation when there are two genes involved. 3.1) Use the following symbols to write out the cross: Male: 3 Female: 9 Dark body color (ebony) = e Wild-type body color: E or E+ Rudimentary wings- (vestigial wings= v) Wild-type wings: V or V+ 3.2) What would the cross look like if...
I included everything here , but i only need help with parts
C-F
You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body...
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