Homework Answers
Okay, so we have 2 loci, one corresponds to abscense/presence of color (P), the recessive p allele gives color absence leading to a white flower independently of any other locus, while the dominant P+ allele gives color presence and the specific color is determined by the second locus:
The second locus determines the coloration, it has 3 alleles, recessive R+ that gives purple color, dominant Ra allele gives pink color, and the dominant Rb gives red color.
For this we have to make the crossing with a punnet square and then asign the correct phenotype to each individual in the offspring.
a) The parents are: R+Ra P+p and R+R+ P+p
| R+P+ | R+p | RaP+ | Rap | |
| R+P+ | R+R+P+P+ (Purple) | R+R+P+p (Purple) | R+RaP+P+ (Pink) | R+RaP+p (Pink) |
| R+p | R+R+P+p (Purple) | R+R+pp (white) | R+RaP+p (Pink) | R+Rapp (white) |
We have 3 purple, 3 pink and 2 white out of 8 genotypes. So the frequencies ares:
Purple: 3/8 = 0.375
Pink: 3/8 = 0.375
White: 2/8 = 0.25
b) The parents are: R+Rb pp and R+Rb P+p
| R+P+ | R+p | RbP+ | Rbp | |
| R+p | R+R+P+p (purple) | R+R+pp (white) | R+RbP+p (red, maybe purple) | R+Rbpp (white) |
| Rbp | R+RbP+p (red, maybe purple) | R+Rbpp (white) | RbRbP+p (red) | RbRbpp (white) |
Considering all the heterozygous R+Rb have got to be Red (80%), then we have 3 red, 4 white and 1 purple out of 10 plants. The frequencies are:
Red: 3/8 = 0.375
White: 4/8 =0.5
Purple: 1/8 = 0.125
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