The following is data derived from a two factor cross. What is the mutation order and distances. (Hint am47 is at one end of the map)
The more the distance between two genes the more is recombination frequency because crossing over is high and when we compare to the map the mutation will follow the same order.
help solve 1) The following is data derived from a two factor cross. What is the mutation order and distances. (Hint am47 is at one end of the map) Cross Recombination frequency am47 x am 104 am47 x am 101 am 101 x am 104 am47 x am 102 am 102 x am101 am47 x am29 am29 x am101 am 102 x am64 am47 x am64 0.13 0.23 0.09 0.83 0.58 0.39 0.16 0.11 0.72
Would like help& explanation of how the genetic distances factor in. thanks! Three plant genes, A, B, and C, are linked and occur in the following order. Genetic distances are given as map units (m.u.): А. 10 m.u. В. Om.u._C The genes underlie the following phenotypes: A/=blue flowers, a/a = white flowers B/_=tall stems, b/b = short stems CI_ = green leaves, c/c = red leaves You cross two individuals with the following genotypes: AbC/ AC x aBc/aBc you self...
9. You have been asked to determine the map distances between two SNP loci R and Q in wheat. The following cross was undertaken: RARG QcQrx RARA QcQc and yielded progeny as shown below. RARA QrQc RARA QcQc 259 235 242 264 What are the genotypes of the parents of this cross? a) Give the map distance in centiMorgans between these two loci. (Show your work) c) Can you reject hypothesis of no linkage using a Chi-square test? (Show your...
If a plant grown from a blue wrinkled seed (from forat cross; remember there were 169 of them) is crossed to a plant grown from a yellow smooth seed (also from the first cross). What kinds of kernels would be expected (given you know their map distances - 10.7 cM) and in what proportions? A_ - blue aa - yellow W_ - smooth ww - wrinkled
2. A cross is made between two . coli strains: Hfr arg+ bio+leu+ X F arg-bio-leu-. Interrupted mating studies show that arg+ enters the recipient last, and so arg+ recombinants are selected on a medium containing bio and leu only. These recombinants are tested for the presence of bio+ and leu+. The following numbers of individuals are found for each genotype: arg+ bio+ leu+ 320 argt bio- leu+ 0 arg+ bio+ leu-8 arg+ bio- leu 48 a. What is the...
The following table summarizes the results from a two-factor study with 2 levels of factor A and 3 levels of factor B using a separate sample of n = 8 participants in each treatment condition. (Hint: Start with the df values.) Source df MS Between treatments 72 6.00 Ax B Within treatments Total 12 126
By analyzing the gametes from a trihybrid fruit fly that is heterozygous for three linked genes (AaBbDd), you obtain the following data: Organize the 8 haploid genotypes into pairs that correspond to parentals, double crossovers (DCO) and each of the two types of single crossovers (SCO). Draw a map showing the order of the three genes on the chromosome. Label the map to indicate the distances (in centimorgans or map-units) between the gene in the middle and the genes on...
model is appropriate. The cross-sectional relationship Assume a two-factor API between expect return and factor loadings indicates the price of factor 1 is 0.15 and the price of factor 2 is-02. Furthermore, you have estimated factor loadings for stock s X and Y as follows: Asset biib2 X 1.4 0.4 Y0.90.2 and the expected return on an asset having zero loading on both factors is 0.05. According to the APT, what are the approximate equilibrium returns of each of the...
No 4. a) Stocks have a two-factor structure. Two widely diversified portfolios have the following data. Portfolio A has average return 10% and factor betas 1.5 and 0.4, respectively, on the first and second factor. Portfolio B has average return 9% and factor betas 0.2 and 1.3, respectively, on the first and second factor. The risk free return is 2%. What are the risk premia for factors one and two? b) A firm owns a collection of illiquid assets. Returns...
Data 1. Data 2 Rb min y ——— 4. 108 + + + ———— 34. 257 Rb min + ——— 6. 42 + + y —————12. 58 Rb + y ————15. 93 + m + ————3. 89 + m y ———— 0. 33 Rb + c ————24. 84 There are two sets of data, determine which are the parental recombinant region 1 and 2, the double crossover types and the order that the genes are including their map distance Calculation...