Question

Please answer all of the following questions and show all work as well please.

You are examining snacking behavior in your dorm. You've determined that late night snacking is a dominant trait (M_) compared to people that actually get sleep (mm). You genotype (with permission, of course!) all of the students in your dorm and get the following results: MM = 67, Mm = 23, and mm = 10. Which of the following statements is true about your dorm population? If the entire dorm population randomly mated, (1) the frequency of 'midnight snackers' in the next generation is expected to be 0.954. The frequency of 'early to bed'-ers in your dorm (2) means that the frequency of that phenotype in your dorm (10%) is the same in a different dorm. The genotype frequencies in the next generation (3) (after one generation of random mating) of 'early to bed'-ers is expected to be 0.616. The allele frequency of the 'midnight snacker' allele in your dorm population is 0.818.

Answer 1

Question 1

• Ans : Option 2
• $\bigcirc$ The frequency of early to bed-ers in your dom means that the frequency of that phenotype in your dom (10%) is the same in a different dorm

Reason : Given , out of 100 population

MM = 67, Mm = 23, mm = 10

From this dominant trait is expressed in both MM and Mm. i.e. 90 of the population allele express M (late night snacking). 10% will be early bed-ers.

Question 2

• Ans : Option 1
• $\bigcirc$13 individuals are Type O

Reason : The ratio of Type O, fC = 0. 63. That is the probability of individual to have Type blood is 0.63.

Therefore, If 20 individuals are there, the probability to have Type O will be

20 X 0.63 = 12.6 $\simeq$ 13.

Question 3

• Ans : Option 1
• $\bigcirc$ 22.1%

Reason : Lactase persistent individuals require atleast one dominant allele. Therefore probability the cappuccino to be homozygous dominant will be 1/3 of 72%.