The correct chi square value
for question 8 is 4.9. Given that value, I need help with 9&10.
Thanks so much
Homework Answers
Answer:
8). Chi-square value = 4.9
9). Approximate P value = 0.05
Explanation:
Based on the information, the results correlate with Dihybrid testcross which would be 1:1:1:1 expected ratio. It means that each phenotype would be ¼ .
|
Phenotype |
Observed(O) |
Expected (E) |
O-E |
(O-E)2 |
(O-E)2/E |
|
BE |
74 |
87.00 |
-13.00 |
169.00 |
1.94 |
|
Be |
95 |
87.00 |
8.00 |
64.00 |
0.74 |
|
bE |
99 |
87.00 |
12.00 |
144.00 |
1.66 |
|
be |
80 |
87.00 |
-7.00 |
49.00 |
0.56 |
|
Total |
348 |
348.00 |
4.90 |
Chi-square value = 4.9
DF = number of categories – 1
DF = 4-1=3
Approximate P value = 0.05
Critical value = 7.815 (at 0.05 with 2 DF)
The chi-square value of 4.9 is less than the critical value of 7.815. Hence we can accept the null hypothesis and the population is in Hardy-Weinberg equilibrium
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