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QUESTION 8 A cross was made and the following phenotypes were obtained: 74 BE Be DE be What is the chi square value for all cChi Square Value is 4.9. Sorry for not including it


QUESTION 9 4 points Save Answer Given the chi square value from the last question and the critical values table here, what is

QUESTION 10 4 points Your p-value from question 9 suggests: The genes are likely on different chromosomes O recombination is

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Answer #1

Ans: The chi-square value is 4.9.

Explanation:

Phenotypes BE 74 Be 95 BE 99 bo 80 . The assumed null hypothesis is a Observed value (0) Expected Valie (ED) (0-E) (0-5)2 -13

Ans: <0.005

Explanation: The calculated chi-square value 4.9 is less than the table value 7.815 at 0.05 probability level for 3 DF (4 phenotypic class; n-1=3). The value is also less than the 0.1, 0.005 probability level, so it can be written as <0.005. The value is not equal to the values of 0.05 and 0.025 probability level.

Ans: ​​​​​​​The genes are likely on different chromosomes and recombination acting on phenotypes.

Explanation: The deviation between observed and expected value is not significant, so, the assumed hypothesis is accepted. This insignificant deviation due to independent assortment and the genes are not in the same chromosome.

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