Question

INTERACTIVE QUESTION 14.6 Consider an example in which the Mim gene (for pig- ment production) is epistatic to the B/b gene (for deposi- tion of pigment). Suppose that a dominant allele M is necessary for the production of the black pigment mela- nin; mm individuals are white. A dominant allele B re- sults in the deposition of a lot of pigment in an animal's hair, producing a black color. The genotype bb produces Phenotype Genotype Ratio Black M_bb I SS gray hair, assuming the presence of at least one M allele. Two black animals heterozygous for both genes are bred. Fill in the following table for the offspring of this MmBb x MmBb cross.

Answer 1

I am explaining through punnet square.

And it is the case of DOMINANT EPISTATIS.

12:3:1

Girens- epietatie caces Mom gene pigmentation prod. epistatic to Blb gene depoeltion of pigmentation ₃M necesary for black pigment M--- Black. → mm are white Mobb gray → B → producing black odor mmbb white e bb. i gray haur Mm Bb x MB MЬ MB Mb MmBb. Me Мь m 2 , MB / Mb MBI MMBB. I MMBL I mB MmBB Imb MmBb B Membb Mb MMBL | MM BB 1 Mm Bb итувь MB 1 MMBB I MmBbl mm BB BT mb MmBb . Mmbb mmbb ro mm Bb kalio Genotype M-- - Phenotype • Black 1. Gray M-bb White mmbb DOMINANT EPISTATIS