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QUESTION 2 Using the DNA data for the beetle species listed in the table below, complete all of the following instructions an

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Answer #1

a)

difference between Scarites and Pheropsophus

there are 6 differences in both sequences of these two genera

total nucleotide : 26

26 --> 100%

then % for 6 = 6 x 100 / 26

= 23.07 % difference

difference between Scarites and Brachinus armiger

7 differences

= 7 x100 / 26

= 26.92 % difference

difference between Scarites and Brachinus hirsutus

6 differneces

= 23.07%

difference between Scarites and Aptinus

3 differences

= 3 x 100 / 26

= 11.53 %

b)

Aptinus > Pheropsophus > Brachinus hirsutus > Brachinus armiger

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