Question

12/25 answered Click on glycolysis if would like to review it in details. Glucose Preparatory phase first ATP Phosphorylation of glucos and its conversion to glyceraldehyde 3-phosphat Priming © > ADP Glucose 6-phosphate 1-0 Hz Hexokinase ΝΟΗ Η e Phosphohexose isomerase Fructose 6-phosphate ATP (8 Phospho- fructokinase-1 primins и он -OCH, CH-OH HOH он и ©--CH, CH-0- Кинон Aldolase ADP Fructose 1,6-bisphosphate (6) Triose phosphate somerase eleava oferte suar phosphate to two carbon sur phosphate Glyceraldehyde 3-phosphate udehyde a phosphate y 0-0-7- 0-0-0, on Dihydroxyacetone phosphate Payoff phase Oxidative conversion of glyceraldehyde 3-phosphate to Pyruvate and the coupled Glyceraldehyde 3-phosphate (2)

Answer 1

Ans- complete oxidation of one molecule produce- 2 pyruvate, 4 total ATP, 2 net ATP, 2 NADH

option A is when 10 pyruvate form than net ATP is 10, not 20

option B is wrong when 20 pyruvate produce than 20 NADH form, not 10

option C is right when 20 pyruvate form than produce 40 total ATP, 20 net ATP, and 20 NADH

option D is wrong when 10 pyruvates produce than 10 net ATP and 10 NADH form, not 20 net ATP and 20 NADH

So the right answer is option C 20 pyruvate, 40 total ATP,20 net ATP, and 20 NADH