Question

A person with mass ma = 75 kg stands on a spinning platform disk with a radius of R = 1.71 m and mass m-188 kg. The disk is initially spinning at ω = 1 rad/s. The person then walks 2/3 of the way toward the center of the disk (ending 0.57 m from the center). 1)What is the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk? kg-m2 2)What is the total moment of inertia of the system about the center of the disk when the person stands at the final location 2/3 of the way toward the center of the disk? kg-m2 3) What is the final angular velocity of the disk? rad/s 4)What is the change in the total kinetic energy of the person and disk? (A positive value means the energy increased.) J 5)What is the centripetal acceleration of the person when she is at R/3? m/s 6) If the person now walks back to the rim of the disk, what is the final angular speed of the disk? radis

Answer 1

4943 3 (49 3(300) (2-3) (0s)