Answer :)
To calculate allele frequency, use the following method:
Suppose each genotype frequency is in the share of x.
In fitness set a, if the frequency is in equilibrium:
W11(x) + W12(x) + W22(x) = 1
1x + 1x + 0.9x = 1
2.9x = 1
X = 1/2.9
X = 0.345
W11 is the fitness of genotype AA, which has frequency 0.345.
Therefore, allele frequency A (p) = square root of 0.345
Allele frequency A (p) = 0.587
Therefore, allele frequency of recessive allele a (q) = 1 – 0.587
Allele frequency of recessive allele a (q) = 0.413
That is how we proceed for each set,
Again in the set b:
W11(x) + W12(x) + W22(x) = 1
1x + 0.95x + 0.9x = 1
2.85x = 1
X = 1/2.85
X = 0.35
Therefore, allele frequency A (p) = square root of 0.35
Allele frequency A (p) = 0.59
Therefore, allele frequency of recessive allele a (q) = 1 – 0.59
Allele frequency of recessive allele a (q) = 0.41
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