Question

A piston cylinder has 1.6 kg of air at 280K and 110 kPa. It is now heated up in a two step process. First constant volume to 950 K (state 2) then followed by a constant pressure process to 1500K, state 3. Find the final volume and the work in the process. ky Consider air as an ideal gas. Ratr = 0.287 kg P2 The two processes are: 1 -> 2: Constant volume V-V 2 -- 3 Constant pressure Po-P2

Answer 1

110 Ty = 1500 3 (P2, V., Iv) 2 PV = (V,V,') nais NR Tz P2 V 2 + PI) th Piv, ī P, V, Tz. "P, T = P2 T 7 CP) Ta = 950k, I = Ho200 110x 103 Pa R, 7 110 x 10 x 950 Pi 200 373.21 X 10² Pa = P2 (12 = 373Kpa) Pa = 1; I lso barie process)

P, V, EART, P₃ Uz = nRTs Prvi Т. B P₂ \V3 P₂ = P₂ = 373k pa T,=200K, I3 = 1500k P,= lookpa 2 로 = final volume. sn 6))" sn Pi } I VI TI 110 x103 x15oo 373 x103 (280 =(0.295 x 5:36 ) x. > : لا ) 1.50V) (Pr = MRT,) y = MR 7, P. 3 4-5 8 x 7.6 x 0.287x10x 280 V = 0.725 X200 (1.846 m 110