1.
a.
All offspring are red. Both males and females are red.1 :1 ratio of male and female.
b.
If there are 100 offspring, 50 of them have to be red males and 50 red females .
We reject the hypothesis because chi-square is much higher than the P value.
c.
d.
Here there is no difference between the expected and observed at all. So, we accept the Null hypothesis.
Genetics questions, i need help! 1) For the Drosophila red/white cross, you crossed red females and...
29, In fruit flies, red eyes are dominant over white eyes. The gene for eye color (R) is found on the X chromosome (X^R). Females have 2 X chromosomes and males are XY. Fill in the following (case sensitive!): Genotype of a white eyed female: Possible female gametes; separate gametes with a comma (,): Genotype of a red eyed male: Possible male gametes; separate gametes with a comma (,): In fruit flies, red eyes are dominant over white eyes. The...
You are working with Drosophila, and cross females from a true-breeding strain with white eyes to males from a true-breeding strain with red eyes. You examine 200 offspring (100 males and 100 females) from this cross. Which of the following matches the expected outcome? A) 100 red-eyed females, 100 red-eyed males B) 100 red-eyed females, 100 white-eyed males C) 50 red-eyed females, 50 white-eyed females, 50 red-eyed males, 50 white-eyed males D) 100 red-eyed females, 50 red-eyed males, 50 white-eyed...
Chi square: You cross a red heterozygous flower with a white homozygous flower and get the following progeny: 55 red and 45 white. You hypothesis that the plants are following Mendelian Genetics inheritance rules. You preform a chi-square analysis to test your hypothesis. Do you.. a. not accept your hypothesis b. accept your hypothesis c. reject your hypothesis d. fail to reject your hypothesis
2. You cross a homozygous wildtype female Drosophila (fruit fly) with a male that has a black body (bb). You mate two of the F1 (first generation) flies and examine the F2 (second generation) offspring. The phenotypes can be seen in the table below. a. Draw a pedigree to show the P, F1, and F2 generations. You only need to draw one fly with each phenotype for the F2 generation. seen in this cross. the expected values for a cross...
figure 4.13 *22. When Bridges crossed white-eyed females with red-eyed males, he obtained a few red-eyed males and white-eyed females (see Figure 4.13). What types of offspring would be produced if these red-eyed males and white-eyed females were crossed with each other? P generation White-eyed female Red-eyed male Separation of XS (90% of time) Nondisjunction of Xs (10% of time) Cametes y Fertilization F, generation Sperm XXY X"YY Red-eyed female White-eyed male |XWY Progeny resulting from separation of Xs X*X"...
can someone verify this? In Drosophila, alternate alleles of an X chromosome gene, white, determine red eyes (w') and white eyes (w). Alternate alleles of a second X chromosome gene, yellow, determine brown body ) and yellow body (). In cross series A and B, the F1 females are heterozygous for both genes, but the arrangement of alleles in the parental generation is different in each case. Study the genotypes and phenotypes of the P, F1, and F2 flies in...
Finally, bow-legs is hypothesized to be X-linked recessive in Drosophila melanogaster. The P1 virgin females were, once again, homozygous wild type but the males were bow-legged. There were 52 wild type males and 67 wild type females in the F1 generation. The F2 generation contained 30 wild type males, 75 wild type females, 40 bow-legged males and no bow-legged females. Does this data support or reject the hypothesis? Use chi square to prove your position.
The following Drosophila crosses were performed Cross 1 Parents: white-eyed straight winged male x red-eyed; curly winged female Progeny: all red-eyed flies, half of which are curly winged Cross 2 (reciprocal cross) Parents: red-eyed curly winged male x white-eyed straight winged female Progeny: white-eyed males and red-eyed females, half of each have curly wings. Test crosses with the curly winged progeny from cross 1 and 2 to homozygous straight winged flies resulted in all half curly and half straight winged...
3. Ho w would you explain the appearance of 3 white-eyed males along with the 1,237 red-eyed offspring obtained by Morgan in F1 of the cross cited on page 1? Determine the genotype of these flies using a Punnett square.
Cross 1: wildtype x white eyes/yellow bodies Fi: Females- 80 wildtype Males- 121 white eyes/yellow bodies The Fı generation is selfed producing: F2: wildtype White eyes/yellow bodies Wildtype eyes/yellow bodies White eyes/wildtype bodies Females 164 101 Males 132 109 3 How can I produce a chi-square test to test if the genes are sex linked and non-linked?