Question

You are about to ride a steel sled down a surface of ice with an incline of 50 degrees to the horizontal and a distance of 200 m to the bottom of the hill. Draw a free-body diagram for the instant it starts moving. What is the resulting force and acceleration the instant after it starts moving? What is the velocity at the bottom of the hill (initial velocity=0) mus of s= 0,03, mus of k= 0.015. The total mass is 115 kg.

How far will the sled continue to travel horizontally?

If a road is 100. meters from the bottom of the hill, will you survive if a car is coming at the same time you come to a stop?

Answer 1

te mgrina . và 72%, 10 x free body diagram of sled is que for I. mgrino wa maloj 8 mgroso Equation of motion of sled is ma = mgsind- Llang aso Q- glino - Mk Coro) a: 9.8151050 - 0.0/55x40r 50) a = 7.41 mis2 Resulting acceleration - Q: 7.41mız Resulting force = ma: 115x7.41 = 852.471 velocity at bottom is given by V- zad - 2x7.41X200 = 54.44 m/s 54.44 19.8*0.015) 10080.66 m 1980 60 2/ My Horijontal distance - hit with colt it will Not survive