Question

Suppose a woman with a color blind father and a mother with no history of color blindness in her family (i.e. she is homozygous dominant) marries a man with normal color vision. What are the likely genotypes and phenotypes of any children they have. (Note: your probability value should be given as a percentage - %) Briefly explain your answer

Answer 1

Genotype of woman = XcX (because her father was colour blind XcXc)

Genotype of man = XY

XcX × XY

Gametes	X	Y
Xc	XcX normal female	XcY colour blind male
X	XX normal female	XY normal male

Probability of :

Normal female = 100%

Carrier female = 50%

Affected female = 0%

Normal male = 50%

Affected male = 50%

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