here,
the height of object , ho = 2.8 cm
the object distance , d0 = 14.5 cm
the radius of curvature , r = 14.8 cm
focal length , f = r/2
f = 7.4 cm
a)
let the image distance be di
using the mirror formula
1/f = 1/di + 1/do
1/7.4 = 1/di + 1/14.5
di = 15.1 cm
b)
the height of image , hi = ho * ( -di/do)
hi = 2.8 * ( - 15.1 /14.5) cm
hi = - 2.92 cm
Chapter 25, Problem 16 Your answer is partially correct. Try again. Concept Simulation 25.2 illustrates the...
Concept Simulation 25.2 illustrates the concepts pertinent to this problem. A 1.60-cm-high object is situated 14.6 cm in front of a concave mirror that has a radius of curvature of 9.46 cm. Calculate (a) the location and (b) the height of the image.
illustrates the concepts pertinent to this problem. A 2.80-cm-high object is situated 13.1 cm in front of a concave mirror that has a radius of curvature of 13.3 cm. Calculate (a) the location and (b) the height of the image. (a) Number Units (b) Number Units
Mirrors and Lenses O O O O Concave mirror Convex mirror Plane mirror Converging lens Diverging lens Focal length (cm): Object distance, x (cm): Object height (cm): Image distance, x' (cm): Image height (cm): 40.0 200.0 50.0 50.0 -12.5 Concept Questions Notes Audio Intro Oo © Question 6 Concept Simulation 25.2 illustrates the concepts pertinent to this problem. A 2.10-cm-high object is situated 13.4 cm in front of a concave mirror that has a radius of curvature of 12.1 cm....
Chapter 25, Problem 26 GO Your answer is partially correct. Try again. A convex mirror has a focal length of -29 cm. Find the magnification produced by the mirror when the object distance is (a)6 cm and (b)23 cm. EX GE Virtual (a) m- 8.3 cm (b) m2 .6 The answer doesn't have units
Chapter 20, Problem 106 Your answer is partially correct. Try again. Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. How many time constants (a decimal number) must elapse before a capacitor in a series RC circuit is charged to 70.0% of its equilibrium charge? Nu UnitSTNo units the toierance is +/-296 LINK TO TEXT Question Attemptsi Unlimited SAVE FOR LATER SUBHIT ANSWER SUBMIT ANSWER
Chapter 26, Problem 067 Chalkboard Video Your answer is partially correct. Try again. Two converging lenses are separated by 29.00 cm. The focal length of each lens is 19.00 cm. An object is placed 39.00 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right. Object Lens 1 Lens 2 Number 93.63 units/cm 3) the tolerance is +/-2% Click if you would like to Show Work...
Chapter 1, Problem 62 /Your answer is partially correct. Try again Multiple Concept Example 9 provides background pertinent to this problem. The magnitudes of the four displacement vectors shown in the drawing are A 15.0 m, B 11.0 m, C-14.0 m, and D = 28.0 m. Determine the (a) magnitude and (b) direction for the resultant that occurs when these vectors are added together. Specify the direction as a positive (counterclockwise) angle from the +x axis. 20.0 35.0%/1 500. UnitsT...
Chapter 18, Problem 19 Your answer is partially correct. Try again. Multiple-Concept Example 3 provides some pertinent background for this problem. Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which one of the naturally occurring electrons is removed. The radius of the orbit is 3.36 x 10-11 m. Determine the magnitude of the electron's centripetal acceleration. Numb the tolerance is +12% 2o
As an aid in working this problem, consult Concept Simulation 25.3. A convex mirror has a focal length of -46.0 cm. A 12.0-cm-tall object is located 41.0 cm in front of this mirror. (a) Using a ray diagram drawn to scale, determine the location of the image. Note that the mirror must be drawn to scale. 22 x cm (b) Using a ray diagram drawn to scale, determine the size of the image. (Use a negative sign for an inverted...
Chapter 34, Problem 85 GO Your answer is partially correct. Try again. In the figure below, stick figure 0 (the object) stands on the common central axis of two thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 (mounted in box 1) is a converging lens, 0 is at object distance p1 = 3.00 cm, and the distance between the lens and its focal point is 9.00 cm. Lens 2 (box 2) is a diverging lens at...