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how to calculate actual yield in moles and actual yield in grams?
+ CH,CH,CH,CH,OH 1-butanol NaBr + H2SO4 → CH2CH2CH2CH2Br + NaHSO4 + 1,0 sodium sulfuric 1-bromobutane bromide acid 102.9 15.0

15g
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Actual yield in grams is the mass of your product obtained experimentally. Without doing experiment you cant get that137 Now if I consider you got 15 g product as you written below then actual gield inmoles = 15 -0.10gmot actual yielding gram

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