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QUESTION 4 A survey of 100 businesses revealed that the mean after-tax profit was $80,000 and the standard deviation was $12,

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Date: Solution Given that, X 80.000 0= 12,000 n = 100 At 90% Confidence level z is, 2-1-90% = 1-0.90 -0.10 X/2=0.05 Z212= 20.Page No.: Date: Solution Given that X = 377.55 6 = 25 n = 4oo At 95% Confidence level the 2 is, 2 =1-95 % = 1-0.95 -0.05 2/2

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