Question

Many uncatalyzed reactions are slow under physiological conditions. One of the most striking characteristics of enzymes is their catalytic power, which is the ratio of the catalyzed reaction rate constant, kaat, to the uncatalyzed reaction rate reaction constant, kuncat The reaction catalyzed by enzyme A has an uncatalyzed reaction rate constant of 0.18-1 Use the graphs to calculate the catalytic power of enzymes A and B. Enzyme A catalytic power of enzyme A at pH 7: 500000 1,000,000 900,000 800,000 700,000 600,000 500,000 400,000 300,000 200,000 100,000 5 6 7 PH Enzyme B catalytic power of enzyme B: 10 about us Careers privacy policy terms of use contact us help

Answer 1

catalytic power of enzyme A = k_cat (catalized rate constant ) / k_uncat (uncatalized rate constant )

k_cat   = 500,000 s^-1

  k_uncat=   0.1 s^-1

=

500,000s-1/0.15-

Therefore catalytic power of enzyme A    = 5,000,000

Similarly for enzyme B

k_cat = Log (1) s^-1

k_{uncat= Log (-8)} s^-1

=l Log (1) s^-1/ _{Log (-8)} s^-1

^{catalytic power of enzyme B= -0.125} s^-1