Question

Name UNID Class 14 Central Dogma Capstone Worksheet Work together but each student must complete and turn in their own worksheet. 1. In the sequence grid below, you will be guided through filling in all boxes with end label (polarity or directionality). nucleotide, or amino acid. This sequence is from the middle of a coding sequence, you do not need a start sequence Assume that this table is read from LEFT to RIGHT a. The column to the far left identifies the sequence type. Based on the nucleotides given, fill in the words "template and non-template for the two DNA strands as soon as you figure out which is which. (hint: look at mRNA) b. In the second column, write the polarity of the left side of each sequence (5, 3, N or C). c. The remaining columns represent transcriptional and translational alignments. Fill in all nucleotides. d. Using the mRNA codon table provided on the next page, determine the polypeptide sequence. On the codon table, the first nucleotide in mRNA codon is to the left, the second is above, and third is to the right. DNA DNA mRNA codon tRNA anticodon polypeptide 0 G G GLY e. If you read just the mRNA sequence from RIGHT to LEFT instead, what polypeptide would be made? (practice flipping the entire grid to prepare for exam)

Answer 1

Ic DNA (Non template) 5 CGT LANA (Template) 3ATGCCG IGG G C A MRNA codon 5UACGGC AccCGUI IRNA anticodon 3 AUG cc GUGIG GICA Alypeptide TNI Tyre I Gly. I There I Argo e) mRNA - S- UGC CCA CGG CAU-31 polypeptide-N-Cys- Pro-Ang- His -e.

Explanation- The two strands of DNA are complementary to each other. The template strand is complementary to the mRNA sequence except for Thymine which is replaced by Uracil in RNA. The tRNA sequence is complementary to the mRNA sequence. Polypeptide is formed according to the sequence of mRNA.

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