Ans a) We know,
I = C x CR x EF x ED / (BW x AT)
where, I = Intake rate (mg /kg-day)
C = concentration of chemical in mg/m3 = 0.0045
gm/m3 or 4.5 x 10-6 mg/m3
CR = contact rate (m3/day) = 12 m3 /day average inhalation of air for children
EF = Exposure frequency (days/year) = 300 days/year
ED = Exposure duration (in years) = 10 years
BW = Body weight (kg) = 15 kg for children
AT = average period of exposure (days) = (365 days/year x 10 year) = 3650 days
Putting values,
=> I = 4.5 x 10-6 x 12 x 300 x 10 / (15 x 3650)
=> I = 2.95 x 10-6 mg/kg-day
Also, Risk = I x Potency factor
According to given table, Potency factor for Arsenic = 50 kg-day/mg
=> Risk = 2.95 x 10-6 x 50 = 1.475 x 10-4 > 10-6
Since, Risk is more than 10-6 , it is unacceptable
Ans b) acceptable risk = 10-6
We know,
Risk = I x Potency factor
=> I x 50 = 10-6
=> I = 2 x 10-8 mg/kg-day
Also, I = C x CR x EF x ED / (BW x AT)
=> 2 x 10-8 = C x 12 x 300 x 10 / (15 x 3650)
=> 2 x 10-8 = 0.657 C
=> C = 3 x 10-8 mg/m3 or
0.00003
gm/m3
Hence, must reduce its Arsenic concentration to 0.00003
gm/m3 to attain acceptable risk level
Chronic dally irve. It can also be FIGURE 4.10 The potency factor is the slope of...
the lifetime cancer risk (per million) for an adult from eating fish taken from PF 1.75 (oral) and 50 on) in (mg/kg-day): Daily intake of fish 54 g body weight 70 kg (adult) and 15 kg waters containing 0,1 mg/l of Arsenic. 13) Risk CDI x PF: CDI (concentration)x (intake rate)x (exponure) (body weight)x (70 )x (365 29 (chil F Bloconcentration factor for Arsenic 44 /kg: Exposure (350 day/year) x (30 year)l
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someone help me with these questions? having trouble with the
equations.
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