1. In assembling a nucleosome, normally the …(1) histone dimers first combine to form a tetramer, which then further combines with two … (2) histone dimers to form the octamer.
A. 1: H1–H3; 2: H2A–H2B
B. 1: H3–H4; 2: H2A–H2B
C. 1: H2A–H2B; 2: H1–H3
D. 1: H2A–H2B; 2: H3–H4
E. 1: H1–H2; 2: H3–H4
2. There has been a mutation on several enzymes important in DNA replication. For each enzyme, discuss what the protein normally does and how the mutation would impact DNA replication.
a. The mutation affects editing site of the DNA polymerase III so that any incorrect nucleotide cannot slide into the editing site.
b. A mutation occurs which renders DNA ligase does not function.
c. A mutation occurs so that DNA primase does not function.
d. A mutation occurs so that the sliding clamp can no longer bind to the DNA strand.
3. If 30 percent of bases on a strand of DNA are thymine
a. what percentage of bases are adenine?
b. what percentage of bases are cytosine?
c. what percentage of bases are purines?
d. what percentage of bases are pyrimidines?
1.The correct answer would be:B. 1: H3–H4; 2: H2A–H2B
B. 1: H3–H4; 2: H2A–H2B
Reason:During the process of assembly of a nucleosome first H3–H4 and H2A-H2B dimers are formed and then the H3–H4 dimers combine to form tetramers. the H3–H4 tetramer then goes on to combines with two H2A-H2B dimers and this forms the compact octamer core.
2.
The mutation affects editing site of the DNA polymerase III so that any incorrect nucleotide cannot slide into the editing site :DNA polymerase III posseses the ability of proof reading in which any mismatched nucleotide /incorrect base pair is recognised by DNA polymerase III ,excised and then correct nucleotide is inserted,When mutation occurs in editing site of DNA polymerase III ,this incorrect nucleotide will not be correct and the DNA replicarion will continue with the error.
b. A mutation occurs which renders DNA ligase does not function :DNA ligase functions in filling the nicks in the leading strand and in re-annealing the semi-conservative strands and joining the Okazaki Fragments of the lagging strand. When mutation will occur the reannealing of the nicks in leading strand and the okazaki fragments of lagging strand will not be possible.
c. A mutation occurs so that DNA primase does not function:Primase enzyme functions to add primers to the template strands so that DNA replication can start.When the enzyme gets mutated, the primers will not be available for DNA replication to start and DNA replication will not start.
d. A mutation occurs so that the sliding clamp can no longer bind to the DNA strand: Sliding clamp with clamp proteins is formed by clamp proteins that attach to DNA so that DNA polymerase can make contact with the DNA template and carry out the processivity .When mutation occurs, DNA polymerase contact with template will be hindered ,affecting the elongation of replication process.
3.
As per chargaff's rule,
A+G= T+C
Adenine pairs with thymine and guanine pairs with cytosine
if 30% bases are thymine,
then A pairs with T .So, A will be 30%
Now, A+ T = 30+ 30= 60%
so, G+ C = 100 - 60 = 40%
again G pairs with C,
So each will be 20%
a. percentage of bases that are adenine =30%
b. what percentage of bases are cytosine =20%
c. what percentage of bases are purines (adenine + guanine) = 30+ 20 = 50%
d. what percentage of bases are pyrimidines(cytosine+thymine) = 20+30 =50%
1. In assembling a nucleosome, normally the …(1) histone dimers first combine to form a tetramer,...
QUESTION 1 A nucleosome consists of A. a cluster of histone proteins that are wrapped around the DNA double helix. B. two peptides each of histones H2A, H2B, H3 and H4, wrapped by the DNA double helix. the DNA polymerase complex and the Okazaki fragments of approximately 200 bases in C. length. D. clusters of ribosomal large subunits and small subunits bound to the DNA double helix. E. one of each of the 5 types (H1 - H4) of histone...
Question: A diploid nucleus of Drosophila melanogaster contains about 3.4 x 108 nucleotide pairs. Assume (1) that all nuclear DNA is packaged in nucleosomes and (2) that an average internucleosome linker size is 60 nucleotide pairs. How many nucleosomes would be present in a diploid nucleus of D. melanogaster? How many molecules of histone H2a, H2b, H3, and H4 would be required? ANS: In the diploid nucleus of D. melanogaster, 1.65 x 106 nucleosomes would be present; these would contain 3.3...
4. In a lake governed by the food web shown in the image to the right, 500 brown trout are added from fisheries. Which of the following outcomes would most likely be expected? A. Tadpole population will increase B. Duck population will decrease C. Algae population will increase D. Lilly Pad population will decrease E. Caddis Fly larvae will increase 5. Which of the following pieces of evidence most strongly supports a common ancestor of all life on Earth? A....
Why would changes in the genes for transcription factors be expected to generate major phenotypic differences? They are extremely powerful genes. They can affect the expression of small numbers of other genes. Their gene products are remarkably stable. Their gene products normally denature more rapidly than other gene products. They can affect the expression of large numbers of other genes. Which enzyme, also responsible for siRNA formation, carves miRNAs from their double-stranded, fold- back RNA precursor (pre-miRNA)? Dicer ribonuclease RNA...
Genetics Worksheet Week 3: Gene Regulation and Epigenetics 1. Duchenne muscular dystrophy is caused by a mutation in a gene that is 2.5 million nucleotides in length and encodes a protein called dystrophin. The dystrophin protein itself is 3684 amino acids in length. Calculate below the approximate size of the mRNA that encodes dystrophin. Approximately what percentage of the gene that encodes dystrophin is intron sequence? The human genome encodes a much greater variety and number of proteins than the...
PLEASE COMPUTER TYPED* OR VERY CLEAR HANDWRITING with details 1. Radioactive (14C) uridine (lots of it) is added to a growing culture of bacteria for 10 seconds and then the drug rifamycin is added (rifamycin blocks the initiation of transcription, but not continued elongation of RNA polymerases that have already begun transcribing). At two-minute intervals, 1 ml samples are removed and placed on ice. The bacteria are lysed (broken open) and an enzyme is added that will chew up all...