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O ACTIVITY 5.4.1 Synthesis of a Protein: A Simulation Activity In this activity, you will be provided with the DNA nucleotide

OV | ACTIVITY 5.4.1 continued 3. Transcribe the DNA into mRNA. 4. Identify the middle, end, and beginning sequence. Use your

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Answer #1

1. Three DNA sequence given are as follows:

SEQUENCE A

TCTTCCCTCCTAAACGTTCAACCGGTTCTTAATCCGCCGCCAGGGCCCCGCCCCTCAGAAGTTGGT

SEQUENCE B

TCAGAGGTTTTTGCCCCGTAACAACTTGTTACAACATGGTCATAAACGTCAGAGATGGTCAATCTCTTAATGACT

SEQUENCE C

TACAAACATGTAAACACACCCTCAGTGGACCAACTCGCAACATAAACCAAACACCGCTCGCGCCGAAAAAGATATGG

2. Three given sequences split into codons are as follows:

SEQUENCE A

TCT/TCC/CTC/CTA/AAC/GTT/CAA/CCG/GTT/CTT/AAT/CCG/CCG/CCA/GGG/CCC/CGC/CCC/TCA/GAA/GTT/GGT

SEQUENCE B

TCA/GAG/GTT/TTT/GCC/CCG/TAA/CAA/CTT/GTT/ACA/ACA/TGG/TCA/TAA/ACG/TCA/GAG/ATG/GTC/AAT/CTC/TTA/ATG/ACT

SEQUENCE C

TAC/AAA/CAT/GTA/AAC/ACA/CCC/TCA/GTG/GAC/CAA/CTC/GCA/ACA/TAA/ACC/AAA/CAC/CGC/TCG/CGC/CGA/AAA/AGA/TAT/GG

3. The mRNA from the given DNA sequences in as follows:

SEQUENCE A

AGA/AGG/GAG/GAU/UUG/CAA/GUU/GGC/CAA/GAA/UUA/GGC/GGC/GGU/CCC/GGG/GCG/GGG/AGU/CUU/CAA/CCA

SEQUENCE B

AGU/CUC/CAA/AAA/CGG/GGC/UAA/GUU/GAA/CAA/UGU/UGU/ACC/AGU/AUU/UGC/AGU/CUC/UAC/CAG/UUA/GAG/AAU/UAC/UGA

SEQUENCE C

AUG/UUU/GUA/CAU/UUG/UGU/GGG/AGU/CAC/CUG/GUU/GAG/CGU/UGU/AUU/UGG/UUU/GUG/GCG/AGC/GCG/GCU/UUU/UCU/AUA/CC

3. Since sequence C is starting with codon AUG which is the start codon, sequence is the beginning sequence. Sequence B is ending with UGA which the stop codon, it is the end sequence and therefore the remaining sequence A is the middle sequence.

4. The sequence after removing the codons 24 to 66 is as follows:

AUG/UUU/GUA/CAU/UUG/UGU/GGG/AGU/CAC/CUG/GUU/GAG/CGU/UGU/AUU/UGG/UUU/GUG/GCG/AGC/GCG/GCU/UUU/UAC/CAG/UUA/GAG/AAU/UAC/UGA

5. The protein sequence from the above mRNA sequence is as follows:

Met-Phe-Val-His-Leu-Cys-Gly-Ser-His-Leu-Val-Glu-Arg-Cys-Ile-Try-Phe-Val-Ala-Thr-Arg-Ala-Phe-Try-Gln-Leu-Glu-Asn-Tyr-Stop

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