Question

Disulfur dichloride, which has a revolting smell, can be prepared by directly combning Ss and Cla but it can also be made by this reaction 3 SC2 () +4 NaF(s) SF4(g) +S2 Cl2(e) + 4 NaCI(s) Calculate the mas of SCla needed to react with excess NaF to prepare 1.62 g S,Ch if the expected yield is 43%. Mass of SCI,- 10 item attempts remaining

Answer 1

3 Scl_2(l) + 4 Naf(s) - > sfy(g) + S_2Cl_2(l) + 4NaCL(s) 3 mole 1 mole 102.97 times 3 108.07g = 308.91g 3 mole of SCL_2 given 1 mole of sF_y 308.91g of SCL_2 gives 108.07g of sF_y in the above reaction Given experimental yields 1.62g % yield = 43 so we know % yield = experimental yield/theoretical yield times 100 = > 43 = 1.62/T middot Y times 100 = > t middot y = 1.62 times 100/43 = 3.767g of SF_y therefore 108.07 of sF_y is obtained from 308.91 of SCL_2 1g of sF_y is obtained from 308.91/108.07 of SCL_2 3.767g g of sF_y is obtained from = 308.91/108.07 times 3.767 = 10767 g therefore 10.767 g og SCL_2 needed to react with excess NaF to prepare 1.62g of S_2Cl_2 of the expected yield is 43%