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7. 33 mL of 3 M HCl is titrated with NaOH to form water and NaCl. How many moles of NaOH are consumed in this reaction? a. 99
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Answer #1

Balanced reaction: HCl(aq) + NaOH(aq) -----> NaCl(aq) + H2O(l)

Number of moles of HCl used in this reaction = 33mL * 3 mole/1000mL = 99*10^-3 mol = 0.099 moles of HCl

As oer the balanced equation, same number of moles of NaOH are needed to neutralize HCl completely.

Thus the answer is option c) 0.099 mol.

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