You are standing on the edge of a swimming pool and looking directly across at the opposite side. You notice that the bottom edge of the opposite side of the pool appears to be at an angle of 26.0° below the horizontal. However, when you sit on the pool edge, the bottom edge of the opposite side of the pool appears to be at an angle of only 13.2°below the horizontal. Use these observations to determine the width and depth of the pool. Hint: You will need to estimate the height of your eyes above the surface of the water when standing and sitting. (Assume 1.7 m when standing and 0.7 m when sitting.)
Width=__________ m
Depth=_________m
From Snell's law Refractive Index of water
Given and i1 =260 , r1 = 19.20
In the second case i2 = 13.20 r2 = 9.90
From figure given above
Tan260 = 1.7/x
x= 3.49m
Tan13.20 = 0.7/x1
x1 = 3.0m
In the second triangel in both the cases we have
Tan19.20=(w-x)/d and Tan9.90 =w-x')/d
Now, Tan19.20/Tan9.90 = 2
2=(w-x)/(w-x')
The width of the lake is
w= 3.16m
now, d= (w-x1)/Tan9.90 =(3.16-3)/0.175
Depth of the lake d =0.91m
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