Question

Problem#2 (40 points) Scenario: The next afternoon, you and your friends decide to slingshot water balloons from the balcony of your apartment onto a nearby street below. Suppose you launch the water balloon upwards at a 20' with an initial velocity of 30m/s and it took a total time of 3.5 seconds to hit the ground. a) How high up is the balcony from the street? In at m b) What is the maximum height of the water balloon during flight from the street below? c) How long did it take the water balloon to reach this maximum height? d) Calculate the total distance the balloon travels from your balcony until it lands on the street below.

working on it, just need answer for confirmation. test is tmwr.

Answer 1

460) = h, 9(3:55). o , Ay=-9, Viva V, sin20 I y(t) = 410) + Vigt + ayt? 0 = b +(osip 20t) - 92 - 2 & 4, sidzot = 4.8*2.5° - (2045102013-5) b=24,11m At maximum height, vy=0 Voy - You + 2aH => O- v’sio’zo - 24H x²sin 20 30 x sin²20 5.37m 292x9.8 Maximum height from the sweet, Hth = 29:48 Vy a Vig tat to galing k sip20. 30.51820 t=1.055 R xlt) = x(0) + Vix t + ant. V, 605206 - 30x60S 20x3-5 R = 98.67 m