Cross-sectional views of three long conductors carrying currents 11 = 3.4 A, 12 = 1.4 A,...

Question

Question

Cross-sectional views of three long conductors carrying currents 11 = 3.4 A, 12 = 1.4 A, and 13 = 4.2 A are shown in the figu

Answer 1

Answer #1

Loop a 17S solutions As & Biał = Mo I | where I is the current threaded into the loop. so for loop as d Budd = Mo Iz = 48x10

Answer 2

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