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Given that resolving power is calculated as D, the minimum distance that two points can be...

Given that resolving power is calculated as D, the minimum distance that two points can be resolved, what is the resolving power when blue light (λ = 464 nanometers) is used to illuminate the specimen on a microscope where the numerical aperture of the condenser is 1.25 nanometers, and the numerical aperture of the objective lens is 0.7? Report your answer in nanometers rounded to the nearest tenth of a decimal point

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Answer #1

Resalein being Power (D) D = d Nocond & Ntobj 464 hm 1.2 5hm +0.07 nm - 351.5! nm Xoom = 6.3515 XI0 6 0, 351 x 10 m 10osce

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