The right answer here is option c. Phosphorylated S6 and STAT3 show higher intensity bands at 3h, compared to those in the lanes without NaOX treatment.
Option a is wrong as total protein of S6 and STAT3 show more or less uniform intensity signals irrespective of NaOX treatment.
Option b is wrong as Actin bands are of uniform intensity in all samples.
Option d is wrong too as the phosphorylated S6 band intensity is even higher than that of the 3h treatment.
correct answer please Question 12 Complete 0.00 points out of 1.00 P Flag question In addition...
YOUCHSULUI About Courses Help Home My Courses de This course Question 11 Complete 0.00 points out of 1.00 Prof. Weimb's lab in MCDB on UCSB's campus studies polycistic kidney disease. One of his researchers recently published their research that focused on how the renal tubule deals with blockages to the filtrate/future urine flow. See the summary below Flag question Healthy tubule Normal flow • Crystal occludes tubule • Disrupted flow 1. Activation of mTOR, STAT3 • Tubule dilation by hypertrophy...